Online Learning

# Final Stat

Work: Since the Q3 for Quiz 1 is 95 and Q3 for Quiz 2 is 90. Quiz 2 has 25% of students 90 and above whereas the Quiz 1 has Q3 as 95 which means 90 starts even before Q3. So Quiz 1 has more students whose score is 90 and above.
Work: Since the Q2 for Quiz 1 is 60 and Q2 for Quiz 2 is 50. Quiz 1 has 50% of students below 60 whereas the Quiz 2 has Q2 as 50 which means some students above this range has below score 60. So it is more than 50%
Here n(A)=200 and n(B)=100 and n(AB)=80. P(A)=n(A)/N=200/1000=0.2, P(B)=n(B)/N=100/1000=0.1 and P(AB)=n(AB)/N=80/1000=0.08. The probability that a randomly selected junior is taking at least one of these two courses is given by
(a) Since the opponent’s serves which she is able to return is the no. of trials , it is 10 and she is able to return is treated as success it is 30% and p=0.3, the probability of success and q=1- probability of failure=1-p=0.7
Given that xN(10,2) and define a standard normal variable z=(x- μ)/σ=(x-10)/2 which follows N(0,1) so that the probabilities can be obtained form a standard normal table. P(10

Final Stat